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25x^2+21x-4=0
a = 25; b = 21; c = -4;
Δ = b2-4ac
Δ = 212-4·25·(-4)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-29}{2*25}=\frac{-50}{50} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+29}{2*25}=\frac{8}{50} =4/25 $
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